[Solved] A sum of money doubles itself in 7 years when invested at si (2024)

GIVEN:

A sum of money doubles itself in 7 years.

CONCEPT:

Simple interest concept.

FORMULA USED:

SI = (PRT/100)

Where,

P = Principal, R = Rate, T = Time

CALCULATION:

Suppose Principal = Rs. P, Amount = 2P, Time = 7 and Rate = R% (Suppose)

⇒ SI = 2P – P = Rs. P

Now,

P = (P × R × 7/100)

⇒ R = 100/7%

Now, we want the money to be quadruple i.e. 4 times.

⇒ Amount = 4P and SI = 3P

Suppose time = T

So,

3P = (P × 100/7 × T)/100

⇒ T = 21

∴ The money will quadruple itself in 21 years.

[Solved] A sum of money doubles itself in 7 years when invested at si (2024)
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